10x^2-26x-140=0

Solution for 10x^2-26x-140=0 equation:

10x^2-26x-140=0

a = 10; b = -26; c = -140;
Δ = b2-4ac
Δ = -262-4·10·(-140)
Δ = 6276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6276}=\sqrt{4*1569}=\sqrt{4}*\sqrt{1569}=2\sqrt{1569}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{1569}}{2*10}=\frac{26-2\sqrt{1569}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{1569}}{2*10}=\frac{26+2\sqrt{1569}}{20}
$